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Surds and Indices
❨ xb ❩ (b + c - a) . ❨ xc ❩ (c + a - b) . ❨ xa ❩ (a + b - c) =? xc xa xb
xabc
1
xab + bc + ca
xa + b + c
Correct Answer:
1
Explanation:
Given Exp.
=
x
(
b
-
c
)(
b
+
c
-
a
)
.
x
(
c
-
a
)(
c
+
a
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b
)
.
x
(
a
-
b
)(
a
+
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c
)
=
x
(
b
-
c
)(
b
+
c
) -
a
(
b
-
c
)
.
x
(
c
-
a
)(
c
+
a
) -
b
(
c
-
a
)
.
x
(
a
-
b
)(
a
+
b
) -
c
(
a
-
b
)
=
x
(
b
2
-
c
2
+
c
2
-
a
2
+
a
2
-
b
2
)
.
x
-
a
(
b
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c
) -
b
(
c
-
a
) -
c
(
a
-
b
)
= (
x
0
x
x
0
)
= (1 x 1) = 1.
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