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3x2-14x+16=05y2-16y+12=0

Correct Answer: x=y or relation cannot be established between x and y

Explanation:

3x2 – 14x + 16=0


3x2 –6x – 8x + 16=0


3x (x-2) – 8 (x-2)


(3x-8) (x-2)=0


x=8/3 or 2


5y2 – 16y + 12=0


5y2 – 10y – 6y + 12=0


5y (y-2) – 6 (y-2)=0


(5y-6) (y-2)=0


y=6/5 or 2


Can't be determined.


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