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Simplification
1/(tanA + cotA) is equal to
(cosecA + sinA)(secA - cosA)
√[(cosecA - sinA)(secA - cosA)]
√[(cosecA + sinA)(secA - cosA)]
(cosecA - sinA)(secA - cosA)
Correct Answer:
(cosecA - sinA)(secA - cosA)
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