A person divided a sum of Rs. 17,200 into three parts and invested at 5%. 6% and 9% per annum simple interest. At the end of two years, he got the same interest on each part of money. What is the money invested at 9%?

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Accepted Answer

Let sum invested @ 5% be P1, @ 6% be P2 then @ 9% =17200-(P1+P2)

So according to question

P1*5*2/100 = P2*6*2/100 or P1 = (6/5) P2

Also P2*6*2/100 = [17200-(P1+P2)]*9*2/100

Or 2 P2 = [17200–(11/5)P2] * 3

Or (2 + 33/5)P2 = 17200 * 3

P2 = 17200 * 3 * 5 / 43 = 6000

So P1 = 6/5 P2 = 7200

So Sum invested @ 9% = 17200–(6000+7200) = Rs 4000

A person divided a sum of Rs. 17,200 into three parts and invested at 5%. 6% and 9% per annum simple interest. At the end of two years, he got the same interest on each part of money. What is the money invested at 9%?

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