Let the distance between Mokama and Hazipur be D km
Time taken by train P to cover D km = 1 h
Time taken by Q to cover D km = 3/2 h
∴ Speed of train P = D km/h
Speed of train Q = 2D/3 km/h .
Let they cross each other T h after 5 : 00 pm.
Then, DT + 2DT/ 3 = D
⇒ T + 2T/3 = 1
⇒ T(1 + 2/3) = 1
⇒ T = 3/5h = (3/5) x 60 = 3 x 12 = 36 min.
Hence, the two trains meet 36 min after 5 : 00 pm.
∴ Meeting time = 5:36 pm