A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken ?

4/3 hrs
2/3 hrs
3/2 hrs
1/4 hrs

Correct Answer: 2/3 hrs

Explanation:

Let the original speed and time is S and T
then distance = S x T
Now the speed changes to 2/3S and T is T+20
As the distance is same
S x T = 2/3Sx(T+20)
solving this we get t = 40 minutes
=40/60 = 2/3 hour

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