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What is the greatest number that divides 263, 935 and 1383 leaving a remainder of 7 in each case?

30
31
32
35

Correct Answer: 32

Explanation:

The required greatest number is the HCF of (263 - 7, 935 - 7, 1383 - 7)
i.e., HCF of 256, 928 and 1376 = 32

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