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A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

Correct Answer: 9, 50

Explanation:

Let the age of A = A, B = B and C = C


From given


A = 3B


4 years ago,


C-4 = 2(A-4);


After 4 years


A + 4 = 31;


A = 27;
sub in above B, we get B = 9
C = 2(27 - 4) + 4 = 46 + 4 = 50


Hence B = 9yrs and C = 50yrs.


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