Ten years ago A was half of B in age. If the ratio of their present ages is 3 : 4. What will be the total of their present ages?

8 years
20 years
35 years
45 years

Correct Answer: 35 years

Explanation:

Let A's age 10 years ago = x years
Then, B's age 10 years ago = 2x years
∵ (x + 10) / (2x + 10) = 3 / 4
⇒ 4(x + 10) = 3(2x + 10)
⇒ x(6 - 4) = 40 - 30
⇒ x = 5
&ther4; Total of their present ages = (x + 10) + (2x + 10)
= (3x + 20)
= 35 years

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