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The respective ages of father and his son are 41 and 16 years. In how many years will the father be twice as old as his son?

19 years
9 years
10 years
15 years

Correct Answer: 9 years

Explanation:

Suppose x years later the father will be twice as old as his son.
∵ x + 41 = 2 (x + 16)
⇒ x = 41 - 32 = 9 years

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