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The average age of A and B, 2 years ago was 26. If the age of A, 5 years hence is 40 yrs, and B is 5 years younger to C, then find the difference between the age of A and C?

Correct Answer: 9 yrs

Explanation:

Let the present ages of A and B be 'x' and 'y' respectively


From the given data, 


[(x-2) + (y-2)]/2 = 26


=> x+y = 56


But given the age of A, 5 years hence is 40 yrs => present age of A = 40 - 5 = 35 yrs


=> x = 35 => y = 56 - 35 = 21


=> Age of B = 21 yrs


Given B is 5 years younger to C,


=> Age of C = 21 + 5 = 26 yrs


=> Required Difference between ages of A and C = 35 - 26 = 9 yrs.


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