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The ages of Harsh and Sumit are 40 yr and 60 yr, respectively. How many year before the ratio of their ages was 3 : 5?

Correct Answer: 10 yr

Explanation:

Let k yr before, the ratio of their ages was 3 : 5.
According to the question
(40 - k)/(60 - k) = 3/5
⇒ 200 - 5k = 180 - 3k
⇒ 2k = 20
∴ k = 10


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