What is the possibility of getting at least 6 heads, if eight coins are tossed simultaneously?

37/256
25/57
1/13
None of these

Correct Answer: 37/256

Explanation:

Required probability = Probability of getting 2 tails + Probability of getting 1 tail + Probability of getting no tail.
= ⁸C₂ x 1/256 + ⁸C₁ x 1/256 + ⁸C₀ x 1/256
= 37/256

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