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If three marbles are picked at random, what is the probability that either all are green or all are red?

Correct Answer: 1/44

Explanation:

Total number of ways of selection of 3 marbles out of 12
= n(S) = 12C3 = 220
Total number of favorable events = n(E)
= 3C3 + 4C3 = 1 + 4 = 5
∴ Required probability
= 5/220 = 1/44


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