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A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?

Correct Answer: 10/21

Explanation:

Total number of balls = (2 + 3 + 2) = 7.


 


Let S be the sample space.


 


Then, n(S) = Number of ways of drawing 2 balls out of 7 = 7 C 2  = 21


 


Let E = Event of drawing 2 balls, none of which is blue.


 


n(E) = Number of ways of drawing 2 balls out of (2 + 3) balls = 5 C 2  = 10


 


Therefore, P(E) = n(E)/n(S) = 10/ 21.


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