Correct Answer: 90°
Explanation:
In a quadrilateral ABCD,
Given :- ∠B = 90°
AB2 + BC2 + CD2 = AC2 + CD2 = AD2 { ∴ In triangle ABC , AB2 + BC2 = AC2 }
So, in triangle ACD, angle opposite to AD = 90° ( by Converse of Pythagoras theorem)
⇒ ∠ACD = 90°
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