Curioustab

Home » Aptitude » Plane Geometry

In the following figure, ∠B : ∠C = 2 : 3, find ∠B + ∠C.

120°
52°
78°
130°

Correct Answer: 78°

Explanation:

∠DAC = ∠B + ∠C
(Exterior angle prop. of a Δ ABC)
According to question,
130° = 2A + 3A
5A = 130°
A = 26°
∴ ∠B = 52°; ∠C = 78°

← Previous Question Next Question→

More Questions from Plane Geometry

In a ΔABC, if 2∠A = 3∠B = 6∠C, Then ∠A is equal to:
A, B, C are the three angles of a Δ. If A − B = 15° and B − C = 30°. Then ∠A is equal to :
The sides AB and AC of ΔABC have been produced to D and E respectively. The bisectors of ∠CBD and ∠BCE meet at O. If ∠A = 40°, then ∠BOC is equal to:
In the given figure, DE || BC if AD = 1.7 cm, AB = 6.8 cm and AC = 9 cm, find AE.
If the bisector of an angle of Δ bisects the opposite side, then the Δ is :
The areas of two similar Δs are 81 cm 2 and 144 cm 2. If the largest side of the smaller Δ is 27 cm, then the largest side of the larger Δ is :
In the given figure ∠BAD = ∠CAD. AB = 4 cm, AC = 5.2 cm, BD = 3 cm. Find BC.
A ladder 15 m long reaches a window which is 9 m above the ground on one side of street. Keeping its foot at the same point, the ladder is turned to the other side of the street to reach a window 12 m high. What is the width of the street:
D and E are the points on the sides AB and AC respectively of ΔABC such that AD = 8 cm, BD = 12 cm, AE = 6 cm and EC = 9 cm. Then find BC/ DE.
In an equilateral Δ ABC, if AD ⊥ BC, then which option is true?

Discussion & Comments

No comments yet. Be the first to comment!

Join Discussion