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A polygon has 44 diagonals, then the number of its sides are ?

Correct Answer: 11

Explanation:

Let the number of sides be n. 


The number of diagonals is given by nC2 - n  


Therefore, nC2 - n = 44, n>0 


nC2 - n = 44


n- 3n - 88 = 0 


n2 -11n + 8n - 88 = 0  


n(n - 11) + 8(n - 11) = 0 


n = -8 or n = 11.

 


As n>0, n will not be -8. Therefore, n=11.


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