Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

Correct Answer: 25200

Explanation:

Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)

= (⁷C₃ x ⁴C₂)

=	❨	7 x 6 x 5	x	4 x 3	❩
		3 x 2 x 1		2 x 1

= 210.

Number of groups, each having 3 consonants and 2 vowels = 210.

Each group contains 5 letters.

Number of ways of arranging 5 letters among themselves	= 5!
	= 5 x 4 x 3 x 2 x 1
	= 120.

∴ Required number of ways = (210 x 120) = 25200.

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