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A duster is of dimension 5x5x7 all in cms, is sinked into a cylindrical vessel of radius 5 cm and height 10 cm. After insertion the level of the water is inccresed by 2.14 cm. Then by what percentage the part of the duster is above the layer ?

Correct Answer: 4 %

Explanation:

Imension of the duster is assumed as 5x5x7 cm3


Volume of the duster below the water layer
= volume of water increased
= πxrxrxh = 3.14×52×2.14 ≈ 168 cm3


Total volume of the duster = 5×5×7 = 175 cm3


Percentage of the duster part below the layer = 168×100/175 = 96%


Percentage of the duster part above the layer = 4%


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