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What is the greatest of 3 consecutive integers whose sum is 24 ?

Correct Answer: 9

Explanation:

The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3


If the sum is 24, we need to solve the equation 3n + 3 = 24;


=> 3n = 21;


=> n = 7


The greatest of the three numbers is therefore 7 + 2 = 9


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