The sum of first 45 natural numbers is:

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Let S n = (1 + 2 + 3 + ... + 45) This is an A.P. in which a = 1, d = 1, n = 45 and l = 45 ∴Sn = n (a + l) = 45 x (1 + 45) = (45 x 23) = 1035 2 2 Required sum = 1035.

The sum of first 45 natural numbers is:

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