What is the smallest five-digit number that is exactly divisible by 41?

Concept / Approach

• Let the smallest five-digit number be 10000. Find the least multiple of 41 that is ≥ 10000.

Step-by-step calculation
10000 ÷ 41 = 243.902… ⇒ take ceiling to 244Required multiple = 244 × 41 = 10004

Verification
243 × 41 = 9963 < 10000; 244 × 41 = 10004 ≥ 10000.

Final Answer
10004