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If n is natural number , then 6n2+6n is always divisible by :

6 only
6 and 12 both
12 only
by 18 only

Correct Answer: 6 and 12 both

Explanation:

$6 n 2 + 6 n = 6 n n + 1$ , which is always divisible by 6 and 12 both, since n(n+1) is always even.

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