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If n is a natural number, then (6n2 + 6n) is always divisible by:
6 only
6 and 12 both
12 only
by 18 only
Correct Answer:
6 and 12 both
Explanation:
(6
n
2
+ 6
n
) = 6
n
(
n
+ 1), which is always divisible by 6 and 12 both, since
n
(
n
+ 1) is always even.
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