Of the three numbers, the first is twice the second and is half of the third. if the average of three number is 56. the smallest number is?

Question

Accepted Answer

Let the second number be N.
Then, first number = 2N and third number = 4N
∴ 2N + N+ 4N/3 = 56
⇒ 7N = 3 x 56
∴ N = 3 x 56/7 = 24
So, the smallest number is 24.

Of the three numbers, the first is twice the second and is half of the third. if the average of three number is 56. the smallest number is?

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