If the sum of one-half, one-third and one-fourth of a number exceeds the number itself by 4, what could be the number?

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Accepted Answer

Let the number be N ∴ (1/2 + 1/3 + 1/4)N = {(6 +4 +3) x N } / 12 = 13N / 12 According to the question, 13N/12 - N = 4 ∴ N = 48

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