Five time of a position integer is equal to 3 less then twice the square of that number. Find the number.

Q: Five time of a position integer is equal to 3 less then twice the square of that number. Find the number.

Let the number be N According to the question 5N = 2N2 - 3 ⇒ 2N2 - 5N -3 = 0 ⇒ (N - 3) (2N + 1) = 0 N = 3 & -1/2 Thus the required number is 3

3
13
23
33

Correct Answer: 3

Explanation:

Let the number be N
According to the question 5N = 2N² - 3
⇒ 2N² - 5N -3 = 0
⇒ (N - 3) (2N + 1) = 0
N = 3 & -1/2
Thus the required number is 3

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