The digit in the units place of a number is equal to the digit in the tens place of half of that number and the digit in the tens place of that number is less than the digit in units place of half of the number by 1, If the sum of the digits of the …

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Let 1/2 of the no. = 10x + y
and the no. = 10v + w
From the given conditions,
w= x and v = y-1
Thus the no. = 10 (y-1) + x
∴ 2(10x + y ) = 10 (y-1) + x
⇒ 8y - 19x = 10 ...(i)
v + w = 7
⇒ y-1 + x = 7
∴ x + y = 8
Solving equations (i) and (ii) , we get
x = 2 and y = 6
∴ From equations (A)
Number = 10 (y - 1) + x = 52.

The digit in the units place of a number is equal to the digit in the tens place of half of that number and the digit in the tens place of that number is less than the digit in units place of half of the number by 1, If the sum of the digits of the number is seven, then what is the number?

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