In a group of equal number of cows and herdsmen, the number of legs was 28 less than four times the number of heads . The number of herdsmen was

Suppose the number of cows = a therefore , the number of herdsmen = a
The total number of legs = Legs of cows + Legs of herdsmen ( Cow has 4 legs and herdsmen has 2 legs )
The total number of legs = a x 4 + a x 2 = 4a + 2a = 6a
The total number of heads = Heads of cows + Heads of herdsmen ( Cow has 1 head and herdsmen has also 1 head )
The total number of heads = a + a = 2a
According to question,
The total number of legs was 28 less than four times the number of heads,
6a = 4 x 2a - 28
⇒ 8a - 28 = 6a
⇒ 8a - 6a = 28
∴ a = 28/2 = 14