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The shadow of a tower when the angle of elevation of the sun is 45°, is found to be 10 m longer than when it was 60° . The height of the tower is

5(√3 - 1) m
5(√3 + 1) m
10 (√3 - 1) m
10 (√3 + 1) m

Correct Answer: 5(√3 + 1) m

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