From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

Q: From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

Given Tower height = 100 m. Angle of elevation from point P = 30°. Distance from foot to P tan 30° = height / distance ⇒ 1/√3 = 100 / dd = 100√3 = 100√3 m

Difficulty: Easy

100 m
100√3 m
200 m
200/√3 m

Correct Answer: 100√3 m

Explanation:

Given

Tower height = 100 m.
Angle of elevation from point P = 30°.

Distance from foot to P
tan 30° = height / distance ⇒ 1/√3 = 100 / dd = 100√3 = 100√3 m

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