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Height and Distance
From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:
149 m
156 m
173 m
200 m
Correct Answer:
173 m
Explanation:
Let AB be the tower.
Then, ∠APB = 30° and AB = 100 m.
AB
= tan 30° =
1
AP
√3
⟹ AP
= (AB x √3) m
= 100√3 m
= (100 x 1.73) m
= 173 m.
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