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From a point P on a level ground, the angle of elevation of the top tower is 30°. If the tower is 100 m high, the distance of point P from the foot of the tower is:

Correct Answer: 173 m

Explanation:

Let AB be the tower.


Then, ∠APB = 30° and AB = 100 m.



AB = tan 30° = 1
AP √3



⟹ AP = (AB x √3) m
= 100√3 m
= (100 x 1.73) m
= 173 m.
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