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HCF and LCM
The smallest number which when diminished by 7, is divisible by 12, 16, 18, 21 and 28 is
1008
1015
1022
1032
Correct Answer:
1015
Explanation:
Required Number = (L.C.M of 12, 16, 18,21,28)+7
= 1008 + 7
= 1015
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