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In a palace, three different types of coins are there namely gold, silver and bronze. The number of gold, silver and bronze coins is 18000, 9600 and 3600 respectively. Find the minimum number of rooms required if in each room should give the same number of coins of the same type ?

Correct Answer: 26

Explanation:

Gold coins = 18000 , Silver coins = 9600 , Bronze coins = 3600


Find a number which exactly divide all these numbers 


That is HCF of 18000, 9600& 3600 


All the value has 00 at end so the factor will also have 00.


HCF for 180, 96 & 36.


 


Factors of  


180 = 3 x 3 x 5 x 2 x 2


96 = 2 x 2 x 2 x 2 x 2 x 3 


36 = 2 x 2 x 3 x 3 


Common factors are 2x2×3=12


 Therefore, Actual HCF is 1200


 


  


Gold Coins 18000/1200 will be in 15 rooms


Silver Coins 9600/1200 will be in 8 rooms


Bronze Coins 3600/1200 will be in 3 rooms


Total rooms will be (15+8+3)  =  26 rooms.


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