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HCF and LCM
A heap of coconuts is divided into groups of 2, 3 and 5 and each time one coconut is left over. The least number of Coconuts in the heap is ?
63
31
16
27
Correct Answer:
31
Explanation:
To get the least number of coconuts :
LCM = 30 => 30 + 1 = 31
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