What was the day on 15th august 1947 ?

To find the day of the week for any given date, we can use a formula called Zeller's Congruence. Here are the steps:

1. Write down the date: 15th August 1947.
   • Day (q) = 15
   
   
   • Month (m) = 8 (August)
   
   
   • Year = 1947, so we get:
     • K = 47 (last two digits of the year)
     
     
     • J = 19 (first two digits of the year)


2. Apply the formula:
   The formula for Zeller's Congruence is:
   h = (q + floor(13(m + 1) / 5) + K + floor(K / 4) + floor(J / 4) - 2J) mod 7


3. Plug the values into the formula:
   h = (15 + floor(13(8 + 1) / 5) + 47 + floor(47 / 4) + floor(19 / 4) - 2(19)) mod 7


4. Calculate the terms:
   • floor(13(9) / 5) = floor(117 / 5) = 23
   
   
   • floor(47 / 4) = 11
   
   
   • floor(19 / 4) = 4


5. Final calculation: h = (15 + 23 + 47 + 11 + 4 - 38) mod 7
   Simplified: h = 62 mod 7 = 6


6. Interpret the result:
   h = 6, which corresponds to Friday (where 0 = Saturday, 1 = Sunday, ..., 6 = Friday).

Thus, 15th August 1947 was a Friday.