Out of three number, the first is twice the second and is half of the third. If the average of the three number is 56, the three number on order are?

Question

Accepted Answer

Let the numbers be 2y, y and 4y ∵ Average = (2y + y + 4y)/3 ⇒ 7y/3 = 56 ∴ y = (3 x 56) / 7 = 24 Hence , the number in order are 48, 24 and 96

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