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The perimeter of a rectangle whose length is 6 m more than its breadth is 84 m. What will be the area of the rectangle?

Correct Answer: 432 sq.mts

Explanation:

Let the breadth of the rectangle = b mts


Then Length of the rectangle = b + 6 mts


Given perimeter = 84 mts


2(L + B) = 84 mts


2(b+6 + b) = 84


2(2b + 6) = 84


4b + 12 = 84


4b = 84 - 12


4b = 72


b = 18 mts


=> Length = b + 6 = 18 + 6 = 24 mts


 


Now, required Area of the rectangle = L x B = 24 x 18 = 432 sq. mts


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