The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is?

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Let breadth = b meters. Then, length = 4b/3 meters. ∵ b x 4b/3 = 300 ⇒ b2 = 300 x 3/4 ⇒ b2 = 225 ∴ b = 15 Hence, required difference = [(Length) - (Breadth) ] = 4b/3 - b = b/3 = 15/…

The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is?

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