If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:

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Take a square of side 4cm and a rectangle having l=6cm and b=2cm then perimeter of square = perimeter of rectangle area of square = 16 sq.cm area of rectangle = 12 sq.cm Hence a >b

If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:

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