How many circular plates of diameter d be taken out of a square plate of side 2d with minimum loss of material?

Q: How many circular plates of diameter d be taken out of a square plate of side 2d with minimum loss of material?

Area of square plate = (Side)2 = (2d)2 = 4d2 Area of circular plate = π (d/2)2 = πd2/4 ∵ Number of square plates = [(4d2)/4] / [(πd2)/4] = (4 x 4)/π ≈ 5 Since, nearest integer value is 5.

8
6
5
2

Correct Answer: 5

Explanation:

Area of square plate = (Side)²
= (2d)²
= 4d²
Area of circular plate = π (d/2)²
= πd²/4
∵ Number of square plates
= [(4d²)/4] / [(πd²)/4]
= (4 x 4)/π
≈ 5
Since, nearest integer value is 5.

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