Find the area of a triangle whose sides measure 13 cm, 14 cm and 15 cm.

Let a = 13, b = 14 and c = 15. Then,  $s=\frac{1}{2}a+b+c$=21

 (s- a) = 8, (s - b) = 7 and (s - c) = 6.

Area = $ss-as-bs-c$ = $21\times 8\times 7\times 6$ = 84 sq.cm