The Different between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is

Let the length of rectangle = L m
∴ Breadth of rectangle = B m
Using conditions from the question,
L - B = 23 ....(i)
2(L + B) = 206
L + B = 103 ....(ii)
On adding Eqs. (i) and (ii), we get
2L = 126
⇒ L = 63 m
⇒ B = 103 - 63 = 40 m
Then , area of rectangle = L x B
= 63 x 40
= 2520 m² .