The area of a trapezium is 384 sq.cm. If its parallel sides in ratio 3 : 5 and the perpendicular distance between them be 12 cm. The smaller of parallel sides is?
Correct Answer: 24 cm
Explanation:
Let the parallel sides be 3a and 5a.
So Area of trapezium = 1/2 x sum of parallel side x perpendicular distance between them.
⇒ 1/2 (3a +5a) x 12 = 384
⇒ 8a = 64
∴ a =8 ∴ Smaller side = 3x = 3 x 8 = 24 cm.
