The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is?

20 cm
24 cm
30 cm
36 cm

Correct Answer: 24 cm

Explanation:

Let the sides of trapezium be 5k and 3k, respectively
According to the question,
(1/2) x [(5k + 3k) x 12] = 384
⇒ 8k = (384 x 2)/12 = 64
⇒ k = 64/8 = 8 cm
Length of smaller of the parallel sides = 8 x 3 = 24 cm

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