The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is?
Correct Answer: 24 cm
Explanation:
Let the sides of trapezium be 5k and 3k, respectively According to the question,
(1/2) x [(5k + 3k) x 12] = 384
⇒ 8k = (384 x 2)/12 = 64
⇒ k = 64/8 = 8 cm Length of smaller of the parallel sides = 8 x 3 = 24 cm
