A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container ?

Q: A container contains 120 lit of Diesel. From this container, 12 lit of Diesel was taken out and replaced by kerosene. This process was further repeated for two times. How much diesel is now there in the container ?

For these type of problems, Quantity of Diesel remained = q 1 - p q n Here p = 12 , q = 120 => 120 1 - 12 120 3 = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.

88.01 lit
87.48 lit
87.51 lit
87.62 lit

Correct Answer: 87.48 lit

Explanation:

For these type of problems,

Quantity of Diesel remained = $q 1 - \frac{p}{q} n$

Here p = 12 , q = 120

=> $120 1 - \frac{12}{120} 3$ = 120 x 0.9 x 0.9 x 0.9 = 87.48 lit.

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