Repeat of loom-weaving time (approximate seconds): A certain industrial loom weaves 0.128 meters of cloth every second. Approximately how many seconds will it take the loom to weave a total of 25 meters of cloth at this constant rate?

Introduction / Context:
This is the same constant-rate calculation expressed again to reinforce technique. With length and per-second weaving speed given, time is the quotient of length by rate. The result is rounded to the nearest sensible whole second as an approximation.

Given Data / Assumptions:

• Rate = 0.128 m/s
• Target length = 25 m
• Constant speed; ignore machine start/stop effects

Concept / Approach:
Apply time = distance / speed with consistent units. No conversions are required because both distance and rate are in meters and seconds, respectively.

Step-by-Step Solution:
t = 25 / 0.128 = 195.3125 sApproximate time ≈ 195 s

Verification / Alternative check:
Back-multiply: 195 s * 0.128 m/s = 24.96 m, which is very close to 25 m, justifying the chosen approximation.

Why Other Options Are Wrong:
200, 210, and 220 are high relative to the exact computation; 170 is far too low given the rate and length.

Common Pitfalls:
Inverting the division or rounding the rate before division, which can noticeably change the result given the small denominator 0.128.

Final Answer:
195