Number System — Costing problem: A chair costs ₹214 and a table costs ₹937. Estimate (to the nearest reasonable thousand) the total cost of 6 dozen chairs and 4 dozen tables.

Introduction / Context:
This applied arithmetic question mixes unit price, dozens, and rounding. The task is to compute an exact total first and then select the nearest appropriate option (an approximation) among the choices provided, which are rounded to convenient thousands.

Given Data / Assumptions:

• Chair price = ₹214 each; quantity = 6 dozen = 72 chairs.
• Table price = ₹937 each; quantity = 4 dozen = 48 tables.
• Select an approximate total matching the closest option.

Concept / Approach:
Calculate each subtotal exactly, add them, then compare to the rounded options. Keeping arithmetic organized avoids digit transposition. Because the options are rounded, pick the nearest value to the exact total.

Step-by-Step Solution:
1) Chairs: 72 × 214 = (70 × 214) + (2 × 214) = 14980 + 428 = 15408.2) Tables: 48 × 937 = (50 × 937) − (2 × 937) = 46850 − 1874 = 44976.3) Total exact cost = 15408 + 44976 = 60384.4) Compare with options: nearest thousand is ≈ ₹60,000.

Verification / Alternative check:
Quick rounding check: 214 ≈ 200, 937 ≈ 940 → 72*200 = 14400; 48*940 = 45120; sum ≈ 59520, still closest to ₹60,000.

Why Other Options Are Wrong:
₹58,000 and ₹55,000 are too low; ₹62,000 and ₹65,000 are slightly high compared to 60,384. ₹60,000 is the best approximation.

Common Pitfalls:
Forgetting that a dozen is 12; misplacing zeros when multiplying by near-1000 numbers; picking a rounded option without computing the exact base first.

Final Answer:
Rs. 60000