Analogy (A1Z26 complement): IE : RV :: KC : ____. Rule: map each letter to 27 − position (A=1 … Z=26).

Introduction / Context:Given IE → RV, note that I(9) maps to R(18) and E(5) maps to V(22). Each pair sums to 27: 9+18=27, 5+22=27. Apply the same to KC.

Given Data / Assumptions:

• K=11 → 27−11=16 → P.
• C=3 → 27−3=24 → X.

Concept / Approach:Use the 27-complement (Atbash-like) mapping independently per letter.

Step-by-Step Solution:K → P; C → X → result “PX”.

Verification / Alternative check:Sum positions: 11+16=27; 3+24=27.

Why Other Options Are Wrong:They do not satisfy the 27-sum complement rule for both letters.

Common Pitfalls:Applying a single shift rather than the complement mapping.

Final Answer:PX.