Syllogism — Chained universals with an existential corollary Statements: 1) All elephants are men. 2) All men are socks. Conclusions: I) Some socks are elephants. II) All elephants are socks. Select the necessary conclusion(s).

Introduction / Context:
This problem uses a chain of two universal inclusions to test both a universal consequence and a standard existential corollary often assumed in exam-style syllogisms when categories are non-empty.

Given Data / Assumptions:

• Elephants ⊆ Men.
• Men ⊆ Socks.
• Ordinary-language assumption: the class “Elephants” is non-empty, permitting an existential conclusion.

Concept / Approach:
Transitivity yields Elephants ⊆ Socks, which directly validates the universal conclusion (II). If at least one elephant exists, that elephant is a sock under the given premises, making “Some socks are elephants” true as well (I). Although the real-world content is absurd, syllogistic validity depends on form, not plausibility.

Step-by-Step Solution:

Verification / Alternative check:
Venn diagram with nested sets (Socks largest, Men inside Socks, Elephants inside Men) shows II immediately and makes I true when Elephants is non-empty — as typically intended in such problems.

Why Other Options Are Wrong:
Any option omitting II ignores transitivity; omitting I ignores the routine existential corollary used in these exams.

Common Pitfalls:
Rejecting a logically valid consequence because the content sounds unrealistic; in syllogisms, form rules over real-world semantics.

Final Answer:
Both Conclusions I and II follow.